Calculate the angle of minimum deviation for an equilateral triangular prism of refractive index $\sqrt{3}$. (in $^{\circ}$)

$A$ ray of light suffers minimum deviation when incident on a prism having an angle of the prism equal to $60^{\circ}$. The refractive index of the prism material is $\sqrt{2}$. The angle of incidence (in degrees) is . . . . . . .

One face of the glass prism is silver polished. $A$ light ray falls at an angle of $45^{\circ}$ on the other face. After refraction,it is subsequently reflected from the silvered face and then retraces its path. The refracting angle of the prism is $30^{\circ}$. The refractive index of the prism is

The figures represent three cases of a ray passing through a prism of angle $A$. The case corresponding to minimum deviation is

The refracting angle of a glass prism is $30^{\circ}$. $A$ ray is incident on one of the faces and is perpendicular to it. The angle of deviation $\delta$ between the incident ray and the ray that leaves the prism is (Refractive index of glass $= 1.5$) (Given: $\sin(30^{\circ}) = 0.5, \sin(48.6^{\circ}) = 0.75$). (in $^{\circ}$)

$A$ thin prism having refracting angle $10^{\circ}$ is made of glass of refractive index $1.42$. This prism is combined with another thin prism of glass of refractive index $1.7$. This combination produces dispersion without deviation. The refracting angle of the second prism should be....$^{\circ}$